Math  /  Algebra

Question{c(1)=20c(n)=c(n1)+10\left\{\begin{array}{l} c(1)=-20 \\ c(n)=c(n-1)+10 \end{array}\right.
Find the 2nd 2^{\text {nd }} term in the sequence. \square

Studdy Solution
Simplify the equation to find c(2) c(2) .
c(2)=20+10=10 c(2) = -20 + 10 = -10
Solution: The second term in the sequence is c(2)=10 c(2) = -10 .

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