QuestionCalculate the energy required to heat 0.30 kg of water from $21.9^{\circ} \mathrm{C}$ to $44.2^{\circ} \mathrm{C}$. Assume the specific heat capacity of water under these conditions is $4.18 \mathrm{~J} \cdot \mathrm{~g}^{-1} \cdot \mathrm{~K}^{-1}$. Be sure your answer has the correct number of significant digits.

Studdy Solution
Ensure the answer has the correct number of significant digits. The least number of significant digits in the given data is three (from the mass, $0.30 \, \text{kg}$).
Thus, the energy required is:
$$Q = 2.80 \times 10^4 \, \text{J}$$
The energy required to heat the water is:
$\boxed{2.80 \times 10^4 \, \text{J}}$