Math  /  Calculus

QuestionCalculate the value of the following limit: limn3n2+n3n25n\lim _{n \rightarrow \infty} \sqrt{3 n^{2}+n}-\sqrt{3 n^{2}-5 n}

Studdy Solution
Evaluate the limit as n n \rightarrow \infty :
As n n \rightarrow \infty , 1n0 \frac{1}{n} \rightarrow 0 and 5n0 \frac{5}{n} \rightarrow 0 , so:
3+1n3\sqrt{3 + \frac{1}{n}} \rightarrow \sqrt{3} 35n3\sqrt{3 - \frac{5}{n}} \rightarrow \sqrt{3}
Thus, the expression simplifies to:
limn63+3=623=33=3\lim _{n \rightarrow \infty} \frac{6}{\sqrt{3} + \sqrt{3}} = \frac{6}{2\sqrt{3}} = \frac{3}{\sqrt{3}} = \sqrt{3}
The value of the limit is:
3 \boxed{\sqrt{3}}

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