QuestionHow many grams of fluorine ($\mathrm{F}_{2}$) are needed for 3.25 moles of carbon tetrafluoride ($\mathrm{CF}_{4}$)? Molar mass of $\mathrm{F}_{2}$ is 38.00 g/mol. [?] g $\mathrm{F}_{2}$

Studdy Solution
Calculate the mass of $\mathrm{}_{2}$.
$$\text{Mass of } \mathrm{}_{2} =6.5 \text{ moles} \times38.00 \mathrm{~g/mol} =247 \mathrm{~g}$$So,247 grams of fluorine, $\mathrm{}_{2}$, are needed to generate3.25 moles of carbon tetrafluoride, $\mathrm{CF}_{4}$.