Math  /  Calculus

QuestionCheck if the function f(x)={ex/(x+1)if x1e1if x=1f(x)=\begin{cases} e^{x /(x+1)} & \text{if } x \neq-1 \\ e^{-1} & \text{if } x=-1 \end{cases} is continuous at x=1x=-1.

Studdy Solution
Since the left-hand limit and the right-hand limit do not exist, and they are not equal to the value of the function at x=cx=c, the function f(x)f(x) is not continuous at x=cx=c where c=c=-.

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