Math  /  Algebra

QuestionIdentify the function for a geometric sequence: A. A(n)=P+(n1)iPA(n)=P+(n-1) i \cdot P B. A(n)=n+(i1)PA(n)=n+(i-1) \cdot P C. A(n)=(n1)(Pn)iA(n)=(n-1)(P \cdot n)^{i} D. A(n)=P(1+i)n1A(n)=P(1+i)^{n-1}

Studdy Solution
Now, let's compare each of the given functions to the general form of a geometric sequence.
A. A(n)=+(n1)iA(n)=+(n-1) i \cdot
This function does not match the general form of a geometric sequence because the term (n1)i(n-1)i \cdot is added to $$, not multiplied.
B. A(n)=n+(i1)A(n)=n+(i-1) \cdot
This function does not match the general form of a geometric sequence because the term (i1)(i-1) \cdot is added to nn, not multiplied.
C. A(n)=(n1)(n)iA(n)=(n-1)( \cdot n)^{i}This function does not match the general form of a geometric sequence because the term (n)i( \cdot n)^{i} is multiplied by (n1)(n-1), not $$.
. A(n)=(1+i)n1A(n)=(1+i)^{n-1}This function matches the general form of a geometric sequence. Here, $$ is the first term, $1+i$ is the common ratio, and $n$ is the term number.
Therefore, the function that represents a geometric sequence is A(n)=(1+i)n1A(n)=(1+i)^{n-1}.

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