Math / Geometry

QuestionComplete the square and write the given equation in standard form. Then give the center and radius of the circle and graph the equa $x^{2}+y^{2}+6 x-2 y-26=0$
The equation of the circle in standard form is $\square$ (Simplify your answer.) The center of the circle is $\square$ (Type an ordered pair.) The radius of the circle is $\mathrm{r}=$ $\square$ .
Use the graphing tool to graph the circle.
Click to enlarge graph

Studdy Solution
Identify the center and radius of the circle:
The center $(h, k)$ is $(-3, 1)$ .
The radius $r$ is $\sqrt{36} = 6$ .
The equation of the circle in standard form is:
$\boxed{(x + 3)^2 + (y - 1)^2 = 36}$
The center of the circle is:
$\boxed{(-3, 1)}$
The radius of the circle is:
$r = \boxed{6}$

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