Math  /  Data & Statistics

QuestionConsider the following frequency table representing the scores on a test. \begin{tabular}{|c|c|} \hline \multicolumn{2}{|c|}{ Scores on a Test } \\ \hline Class & Frequency \\ \hline 304730-47 & 3 \\ \hline 486548-65 & 10 \\ \hline 668366-83 & 14 \\ \hline 8410184-101 & 11 \\ \hline 102119102-119 & 4 \\ \hline \end{tabular}
Step 1 of 5 : Determine the lower class boundary for the fifth class.
Answer

Studdy Solution
Calculate the lower class boundary by subtracting 0.5 from the lower class limit:
1020.5=101.5 102 - 0.5 = 101.5
The lower class boundary for the fifth class is:
101.5 \boxed{101.5}

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