QuestionConsider the following polynomial. $$h(x)=-8 x^{2}(x+9)(x-1)$$
Step 1 of 2: Find the degree and leading coefficient of $\mathrm{h}(\mathrm{x})$.

Studdy Solution
To find the leading coefficient, consider the coefficient of the term with the highest degree when the polynomial is expanded:
- The coefficient from $-8x^2$ is $-8$. - The highest degree term will be formed by multiplying the highest degree terms from each factor: $x^2$ from $-8x^2$, $x$ from $(x+9)$, and $x$ from $(x-1)$.
Thus, the leading coefficient is:
$$-8 \times 1 \times 1 = -8$$
The degree of the polynomial is $\boxed{4}$ and the leading coefficient is $\boxed{-8}$.