Math  /  Calculus

QuestionConsider the function f(x)=10x10+6x73x36f(x)=10 x^{10}+6 x^{7}-3 x^{3}-6. An antiderivative of f(x)f(x) is F(x)=Axn+Bxm+Cxp+DxqF(x)=A x^{n}+B x^{m}+C x^{p}+D x^{q} where AA is \square and nn is \square and BB is \square and mm is \square and CC is \square and pp is \square and DD is \square and qq is \square

Studdy Solution
So, we have A=1011A = \frac{10}{11} and n=11n = 11, B=34B = \frac{3}{4} and m=8m = 8, C=34C = -\frac{3}{4} and p=4p = 4, and D=6D = -6 and q=1q = 1.
Remember, we could also add any constant to F(x)F(x) and it would still be an antiderivative!

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