Math  /  Calculus

QuestionConsider the function f(x)=xe5x,0x2f(x)=x e^{-5 x}, \quad 0 \leq x \leq 2. This function has an absolute minimum value equal to: \square which is attained at x=x= \square and an absolute maximum value equal to: which is attained at x=x= \square

Studdy Solution
Absolute minimum value: 00 at x=0x = 0. Absolute maximum value: 15e\frac{1}{5e} at x=15x = \frac{1}{5}.

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