Question Determine if $\int_{0}^{\infty} 6 e^{-2 x} d x$ converges or diverges. If convergent, calculate its value.

Studdy Solution
The value of the convergent improper integral is the result of the limit.
$$\int_{0}^{\infty} 6 e^{-2 x} d x = 3$$
Therefore, the correct choice is A and the integral evaluates to 3.
A. $\int_{0}^{\infty} 6 e^{-2 x} d x= 3$
B. The improper integral does not diverge.