Math  /  Geometry

QuestionDetermine the center, vertices, foci, and axis of the hyperbola y216x2=1\frac{y^{2}}{16}-x^{2}=1 and graph it.

Studdy Solution
To graph the hyperbola, plot the center, vertices, and foci on the coordinate plane. Draw the hyperbola opening up and down with vertices at (0,4)(0, -4) and (0,4)(0,4) and foci at (0,17)(0, -\sqrt{17}) and (0,17)(0, \sqrt{17}). The asymptotes of the hyperbola are the lines y=±abx=±4xy = \pm \frac{a}{b}x = \pm4x.
The center, vertices, foci, and axis of the hyperbola given by the equation y16x=\frac{y^{}}{16}-x^{}= are (0,0)(0,0), (0,4)(0, -4) and (0,4)(0,4), (0,17)(0, -\sqrt{17}) and (0,17)(0, \sqrt{17}), and x=0x =0 respectively.

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord