QuestionFind the limit as $x$ approaches -2 for $\frac{x^{3}+8}{x+2}$.

Studdy Solution
Calculate the value of the function at $x = -2$.
$$f(-2) =4+4+4 =12$$So, the limit of the function $\frac{x^{3}+8}{x+2}$ as $x$ approaches $-2$ is $12$.