Question Find the probability of 2 girls and 1 boy in a 3-child family, assuming equal chances for boys/girls. (A) $1/3$ (B) $3/8$ (C) $2/3$ (D) $1/4$

Studdy Solution
Calculate the total probability.
$$Total\, probability = \frac{1}{8} + \frac{1}{8} + \frac{1}{8} = \frac{3}{8}$$
The probability of having 2 girls and 1 boy in a 3-child family is $\frac{3}{8}$, which corresponds to option (B) $3 / 8$.