Math / CalculusQuestionDetermine whether f(x)f(x)f(x) approaches ∞\infty∞ or −∞-\infty−∞ as xxx approaches 4 from the left and from the right. f(x)=−1(x−4)2limx→4−−1(x−4)2=□limx→4+−1(x−4)2=□\begin{array}{r} f(x)=\frac{-1}{(x-4)^{2}} \\ \lim _{x \rightarrow 4^{-}} \frac{-1}{(x-4)^{2}}=\square \\ \lim _{x \rightarrow 4^{+}} \frac{-1}{(x-4)^{2}}=\square \end{array}f(x)=(x−4)2−1limx→4−(x−4)2−1=□limx→4+(x−4)2−1=□ □\square□ □\square□Studdy Solutionlimx→4−−1(x−4)2=−∞ \lim_{x \rightarrow 4^{-}} \frac{-1}{(x-4)^{2}} = -\infty x→4−lim(x−4)2−1=−∞ limx→4+−1(x−4)2=−∞ \lim_{x \rightarrow 4^{+}} \frac{-1}{(x-4)^{2}} = -\infty x→4+lim(x−4)2−1=−∞View Full Solution - FreeWas this helpful?
