Math  /  Calculus

Questiondifferentiats cosx\cos ^{x}

Studdy Solution
Solve for dydx \frac{dy}{dx} by multiplying both sides by y y :
dydx=y(xtan(x)+ln(cos(x))) \frac{dy}{dx} = y \left(-x \tan(x) + \ln(\cos(x))\right)
Substitute back y=(cos(x))x y = (\cos(x))^x :
dydx=(cos(x))x(xtan(x)+ln(cos(x))) \frac{dy}{dx} = (\cos(x))^x \left(-x \tan(x) + \ln(\cos(x))\right)
The derivative of y=cosx y = \cos^x is:
dydx=(cos(x))x(xtan(x)+ln(cos(x))) \frac{dy}{dx} = (\cos(x))^x \left(-x \tan(x) + \ln(\cos(x))\right)

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