QuestionDifferentiate $3xy = \sqrt{16x} - \frac{3}{x^3}$ with respect to $x$.

Studdy Solution
Finally, we can solve for $\frac{dy}{dx}$ to get the derivative of $y$ with respect to $x$.
$$3x \frac{dy}{dx} =8x^{-/2} +9x^{-4} -3y$$$$\frac{dy}{dx} = \frac{8x^{-/2} +9x^{-4} -3y}{3x}$$So, the derivative of the given equation with respect to $x$ is $\frac{dy}{dx} = \frac{8x^{-/2} +9x^{-4} -3y}{3x}$.