Math  /  Algebra

QuestionDivide as indicated. Simplify the answer. ab4a+4b÷a2b2a2+6a+9ab4a+4b÷a2b2a2+6a+9=\begin{array}{l} \frac{a-b}{4 a+4 b} \div \frac{a^{2}-b^{2}}{a^{2}+6 a+9} \\ \frac{a-b}{4 a+4 b} \div \frac{a^{2}-b^{2}}{a^{2}+6 a+9}=\square \end{array} \square

Studdy Solution
Substitute the factored forms into the expression:
ab4(a+b)×(a+3)2(ab)(a+b)\frac{a-b}{4(a+b)} \times \frac{(a+3)^2}{(a-b)(a+b)}
Cancel common factors:
1. Cancel aba-b in the numerator and denominator.
2. Cancel a+ba+b in the numerator and denominator.

The simplified expression is:
(a+3)24\frac{(a+3)^2}{4}
The simplified answer is:
(a+3)24\boxed{\frac{(a+3)^2}{4}}

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