Math  /  Geometry

QuestionGegeben sind A=5cm2A=5 \, \text{cm}^{2}, a=80mma=80 \, \text{mm} und γ=90\gamma=90^{\circ}. Welche geometrische Figur ist gefragt?

Studdy Solution
Berechnen Sie den Wert von bbb=5cm28cm=0.625cmb = \frac{5 \, \text{cm}^{2}}{8 \, \text{cm}} =0.625 \, \text{cm}Die andere Seite des Rechtecks beträgt 0.625cm0.625 \, \text{cm}.

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