Math  /  Algebra

QuestionÉtant donné a=logb(16)a=\log _{b}(16),
Exprime logb(8b)\log _{b}(8 b) en fonction de a

Studdy Solution
Substitute logb(8)\log_b(8) back into the expression for logb(8b)\log_b(8b):
logb(8b)=3a4+1 \log_b(8b) = \frac{3a}{4} + 1
This is the expression for logb(8b)\log_b(8b) in terms of aa.
The expression for logb(8b)\log_b(8b) in terms of aa is:
3a4+1 \boxed{\frac{3a}{4} + 1}

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