Math  /  Calculus

QuestionEvaluate: 2x2+7x3x2dx\int \frac{2 x^{2}+7 x-3}{x-2} d x x4+x+4x2+2dx\int \frac{x^{4}+x+4}{x^{2}+2} d x

Studdy Solution
Solve the integrals.
x2dx=x33 \int x^2 \, dx = \frac{x^3}{3}
2dx=2x 2 \int dx = 2x
For the third term, use the substitution u=x2+2u = x^2 + 2, du=2xdxdu = 2x \, dx:
5xx2+2dx=521udu=52lnu=52lnx2+2 5 \int \frac{x}{x^2 + 2} \, dx = \frac{5}{2} \int \frac{1}{u} \, du = \frac{5}{2} \ln|u| = \frac{5}{2} \ln|x^2 + 2|
For the fourth term, notice that 81x2+2dx8 \int \frac{1}{x^2 + 2} \, dx can be solved by recognizing it as a standard integral form:
81x2+2dx=812arctan(x2)=42arctan(x2) 8 \int \frac{1}{x^2 + 2} \, dx = 8 \cdot \frac{1}{\sqrt{2}} \arctan\left(\frac{x}{\sqrt{2}}\right) = 4 \sqrt{2} \arctan\left(\frac{x}{\sqrt{2}}\right)
Combining these, we get:
x4+x+4x2+2dx=x332x+52lnx2+2+42arctan(x2)+C \int \frac{x^4 + x + 4}{x^2 + 2} \, dx = \frac{x^3}{3} - 2x + \frac{5}{2} \ln|x^2 + 2| + 4 \sqrt{2} \arctan\left(\frac{x}{\sqrt{2}}\right) + C
where CC is the constant of integration.
Solution: 2x2+7x3x2dx=x2+11x+19lnx2+C \int \frac{2x^2 + 7x - 3}{x-2} \, dx = x^2 + 11x + 19 \ln{|x-2|} + C
x4+x+4x2+2dx=x332x+52lnx2+2+42arctan(x2)+C \int \frac{x^4 + x + 4}{x^2 + 2} \, dx = \frac{x^3}{3} - 2x + \frac{5}{2} \ln|x^2 + 2| + 4 \sqrt{2} \arctan\left(\frac{x}{\sqrt{2}}\right) + C

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