Math / CalculusQuestionEvaluate limx→7x+2−3x2−49\lim _{x \rightarrow 7} \frac{\sqrt{x+2}-3}{x^{2}-49}limx→7x2−49x+2−3Studdy SolutionRe-evaluate the limit as xxx approaches 7:limx→71(x+7)(x+2+3)=1(7+7)(7+2+3)\lim _{x \rightarrow 7} \frac{1}{(x+7)(\sqrt{x+2}+3)} = \frac{1}{(7+7)(\sqrt{7+2}+3)}limx→7(x+7)(x+2+3)1=(7+7)(7+2+3)1Simplify:=114×(3+3)=114×6=184= \frac{1}{14 \times (3+3)} = \frac{1}{14 \times 6} = \frac{1}{84}=14×(3+3)1=14×61=841 The value of the limit is:184\boxed{\frac{1}{84}}841View Full Solution - FreeWas this helpful?