Question$\int_{0}^{1} \frac{3 x}{4 x^{2}-1} d x$

Studdy Solution
Evaluate the definite integral:
$\frac{3}{8} \left[ \ln|3| - \ln|-1| \right]$
Since $\ln|-1|$ is undefined in the real number system, we consider the principal value, which results in:
$\frac{3}{8} \left[ \ln 3 - \ln 1 \right]$
Since $\ln 1 = 0$, this simplifies to:
$\frac{3}{8} \ln 3$
The value of the integral is:
$\boxed{\frac{3}{8} \ln 3}$