Question$\int_{4}^{5} x \sqrt{x^{2}-16} d x$

Studdy Solution
Evaluate the definite integral:
$$= \frac{1}{3} \left[ 9^{3/2} - 0^{3/2} \right]$$
Calculate $9^{3/2}$:
$$9^{3/2} = (9^{1/2})^3 = 3^3 = 27$$
So, the integral evaluates to:
$$= \frac{1}{3} \times 27 = 9$$
The value of the definite integral is:
$$\boxed{9}$$