Math  /  Algebra

QuestionFactor the following expression completely: y22y80=y^{2}-2 y-80= \square

Studdy Solution
Rewrite the quadratic expression using the numbers found:
The expression can be rewritten as:
y2+10y8y80 y^2 + 10y - 8y - 80
Group the terms to factor by grouping:
(y2+10y)+(8y80) (y^2 + 10y) + (-8y - 80)
Factor out the greatest common factor from each group:
y(y+10)8(y+10) y(y + 10) - 8(y + 10)
Notice that (y+10) (y + 10) is a common factor:
(y8)(y+10) (y - 8)(y + 10)
Thus, the completely factored form of the expression is:
(y8)(y+10) \boxed{(y - 8)(y + 10)}

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