QuestionFill in the table using this function rule. $$y=5 x-1$$ \begin{tabular}{|c|c|} \hline$x$ & $y$ \\ \hline 1 & $\square$ \\ \hline 2 & $\square$ \\ \hline 5 & $\square$ \\ \hline 8 & $\square$ \\ \hline \end{tabular}

Studdy Solution
Simplify the expression:
$$y = 40 - 1$$ $$y = 39$$
The value of $y$ when $x = 8$ is $39$.
The completed table is:
\begin{tabular}{|c|c|} \hline x & y \\ \hline 1 & 4 \\ \hline 2 & 9 \\ \hline 5 & 24 \\ \hline 8 & 39 \\ \hline \end{tabular}