QuestionFind $\delta$ for $\varepsilon=0.1$ in the limit: $\lim _{x \rightarrow 6}-3 x-4=-22$.

Studdy Solution
The value of $\delta$ that works for $\varepsilon=0.1$ is $\delta =0.03333...$.
So, for all $x$ satisfying $0 < |x -6| < \delta$, the absolute difference between $-3x -4$ and $-22$ is less than $\varepsilon=0.1$.