QuestionFind a formula for $f^{-1}(x)$ . Identify the domain and range of $f^{-1}$ . Verify that $f$ and $f^{-1}$ are inverses. $f(x)=\sqrt{x+5}, x \geq-5$ $f^{-1}(x)=$ $\square$ (Simplify your answer.)

Studdy Solution
$f^{-1}(x) = x^2 - 5$ , for $x \ge 0$ .
The domain of $f^{-1}(x)$ is $x \ge 0$ and the range is $y \ge -5$ .
We verified that $f$ and $f^{-1}$ are indeed inverses!

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