Math  /  Algebra

QuestionFind a formula for the general term ana_{n} of the sequence assuming the pattern of the first few terms continues. {72,74,78,716,732,}\left\{\frac{7}{2}, \frac{7}{4}, \frac{7}{8}, \frac{7}{16}, \frac{7}{32}, \ldots\right\}
Assume the first term is a1a_{1}. an=a_{n}=

Studdy Solution
Substitute a1=72 a_1 = \frac{7}{2} and r=12 r = \frac{1}{2} into the formula: an=72(12)n1 a_n = \frac{7}{2} \cdot \left(\frac{1}{2}\right)^{n-1}
The formula for the general term an a_n of the sequence is:
an=72n a_n = \frac{7}{2^n}

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