Question Find the antiderivative of $R(x) = \frac{100 e^{x+5}}{(1+e^{x+5})^2}$, where $x$ is the natural log of a histamine dose in mM. Evaluate the antiderivative at $x=-8.9$ and round to 3 decimal places.

Studdy Solution
Round the answer to three decimal places.
$$R(-8.9) \approx -98.010$$
The value of the principle antiderivative of $R(x)$ at $x=-8.9$ is approximately $-98.010$ when rounded to three decimal places.