QuestionFind all $\theta$ in $[0^{\circ}, 360^{\circ})$ such that $\sin \theta = \frac{\sqrt{3}}{2}$.

Studdy Solution
Therefore, the values of $\theta$ in the interval $\left[0^{\circ},360^{\circ}\right)$ that satisfy $\sin \theta=\frac{\sqrt{3}}{2}$ are $\theta =60^{\circ}$ and $\theta =120^{\circ}$.