QuestionFind all real values of $x$ such that $f(x)=0$. $$f(x)=\frac{-6 x-9}{2}$$

Studdy Solution
Verify that $x = -\frac{3}{2}$ satisfies the original equation by substituting it back into the function $f(x)$.
$$f\left(-\frac{3}{2}\right) = \frac{-6\left(-\frac{3}{2}\right) - 9}{2} = \frac{9 - 9}{2} = \frac{0}{2} = 0$$
The solution is: $$x = -\frac{3}{2}$$