Math  /  Trigonometry

QuestionFind all solutions of the equation in the interval [0,2π)[0,2 \pi). 1tanx=secx-\sqrt{1-\tan x}=\sec x
Write your answer(s) in radians in terms of π\pi. If there is more than one solution, separate them with commas. x=x= \square

Studdy Solution
Check each solution to ensure it satisfies the original equation 1tanx=secx-\sqrt{1-\tan x} = \sec x.
1. x=0 x = 0 : 10=1-\sqrt{1-0} = -1, sec0=1\sec 0 = 1. Does not satisfy.
2. x=π x = \pi : 10=1-\sqrt{1-0} = -1, secπ=1\sec \pi = -1. Satisfies.
3. x=3π4 x = \frac{3\pi}{4} : 1(1)=2-\sqrt{1-(-1)} = -\sqrt{2}, sec3π4=2\sec \frac{3\pi}{4} = -\sqrt{2}. Satisfies.
4. x=7π4 x = \frac{7\pi}{4} : 1(1)=2-\sqrt{1-(-1)} = -\sqrt{2}, sec7π4=2\sec \frac{7\pi}{4} = \sqrt{2}. Does not satisfy.

The solutions in the interval [0,2π)[0, 2\pi) are:
x=π,3π4 x = \pi, \frac{3\pi}{4}

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