QuestionFind $\alpha$ in $[0^{\circ}, 90^{\circ}]$ such that $\csc \alpha = 1.4973691$. Calculate $\alpha \approx$.

Studdy Solution
Calculate the value of $\alpha$.
$$\alpha \approx41.810314^{\circ}$$So, the value of $\alpha$ that satisfies the given statement is approximately $41.81^{\circ}$.