Math  /  Geometry

QuestionFind an equation of the hyperbola that has vertices (0,0)(0,0) and (0,16)(0,-16) and foci (0,2)(0,2) and (0,18)(0,-18).
Equation: \square =1=1

Studdy Solution
Write the equation of the hyperbola:
Since the hyperbola is vertical, the equation is:
(y+8)2a2x2b2=1 \frac{(y + 8)^2}{a^2} - \frac{x^2}{b^2} = 1
Substitute the values of a2 a^2 and b2 b^2 :
(y+8)264x236=1 \frac{(y + 8)^2}{64} - \frac{x^2}{36} = 1
The equation of the hyperbola is:
(y+8)264x236=1 \boxed{\frac{(y + 8)^2}{64} - \frac{x^2}{36} = 1}

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord