QuestionFind $\frac{d y}{d x}$ in terms of $t$ for the equations $x=\sin^3 t$ and $y=\cos^4 t$.

Studdy Solution
implify the expression by canceling out common factors.
$$\frac{d y}{d x} = \frac{-4 \operatorname{Cos}^{2} t}{3 \operatorname{Sin} t}$$So, the derivative of $y$ with respect to $x$ in terms of the parameter $t$ is $\frac{-4 \operatorname{Cos}^{2} t}{3 \operatorname{Sin} t}$.