Math / TrigonometryQuestionSolve for 0∘≤θ<360∘0^{\circ} \leq \theta < 360^{\circ}0∘≤θ<360∘ where cosθ=12\cos \theta = \frac{1}{2}cosθ=21. What are the values of θ\thetaθ?Studdy SolutionTherefore, the solutions to cosθ=12\cos \theta=\frac{1}{2}cosθ=21 given 0∘≤θ<360∘0^{\circ} \leq \theta<360^{\circ}0∘≤θ<360∘ are θ=60∘\theta=60^{\circ}θ=60∘ and θ=300∘\theta=300^{\circ}θ=300∘.The solution is 60∘,300∘60^{\circ},300^{\circ}60∘,300∘. View Full Solution - FreeWas this helpful?