Math / CalculusQuestionFind f′′(x)f^{\prime \prime}(x)f′′(x) f(x)=x1/9f′′(x)=□\begin{array}{r} f(x)=x^{1 / 9} \\ f^{\prime \prime}(x)=\square \end{array}f(x)=x1/9f′′(x)=□Studdy SolutionSimplify the expression for the second derivative:f′′(x)=−881x−17/9 f^{\prime \prime}(x) = -\frac{8}{81}x^{-17/9} f′′(x)=−818x−17/9 The second derivative f′′(x) f^{\prime \prime}(x) f′′(x) is:−881x−17/9 \boxed{-\frac{8}{81}x^{-17/9}} −818x−17/9View Full Solution - FreeWas this helpful?