Math / CalculusQuestionfind ∫ln(x+1)22x+2dx\int \frac{\ln (x+1)^{2}}{2 x+2} d x∫2x+2ln(x+1)2dxStuddy SolutionBack-substitute u=ln(x+1) u = \ln(x+1) u=ln(x+1) into the integrated expression:(ln(x+1))22+C\frac{(\ln(x+1))^2}{2} + C2(ln(x+1))2+C The solution to the integral is:(ln(x+1))22+C\boxed{\frac{(\ln(x+1))^2}{2} + C}2(ln(x+1))2+CView Full Solution - FreeWas this helpful?