Math  /  Trigonometry

QuestionFind the amplitude and period for 1/4sin(πx)-1 / 4 \sin (\pi x)

Studdy Solution
The period of a sine function y=asin(bx) y = a \sin(bx) is given by 2πb \frac{2\pi}{b} .
For the function y=14sin(πx) y = -\frac{1}{4} \sin(\pi x) , the coefficient b b is π\pi.
Therefore, the period is:
Period=2ππ=2 \text{Period} = \frac{2\pi}{\pi} = 2
The amplitude is 14 \frac{1}{4} and the period is 2 2 .

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