Math  /  Geometry

QuestionFind the center of the circle from the equation 225x2+225y2=225225x^{2}+225y^{2}=225. Simplify if needed.

Studdy Solution
Now that we have the equation in standard form, we can identify the center of the circle. The center of the circle is given by the coordinates (h,k)(h, k) in the standard form of the equation.
In this case, since there are no xx or yy terms, we can conclude that the center of the circle is at the origin, (0,0)(0,0).
The center of the circle given by the equation 225x2+225y2=225225x^{2}+225y^{2}=225 is (0,0)(0,0).

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