Math  /  Calculus

Question Find the point on the curve y=tanxy=\tan x closest to (1,1), correct to two decimal places.

Studdy Solution
Round the coordinates (x0,y0)(x_0, y_0) to two decimal places to get the final answer.
Let's assume the rounded coordinates are (x1,y1)(x_1, y_1).
The coordinates of the point on the curve y=tanxy = \tan x that is closest to the point (1,1)(1,1), correct to two decimal places, are approximately (x1,y1)(x_1, y_1).

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