QuestionFind the definite integral. (Use symbolic notation and fractions where needed.) $$\int_{-\pi / 4}^{\pi / 2} \cos (x) d x=$$ $\square$

Studdy Solution
Subtract the value found at the lower limit from the value found at the upper limit:
$$\int_{-\pi / 4}^{\pi / 2} \cos(x) \, dx = 1 - \left(-\frac{\sqrt{2}}{2}\right)$$
$$= 1 + \frac{\sqrt{2}}{2}$$
The value of the definite integral is:
$$\boxed{1 + \frac{\sqrt{2}}{2}}$$