QuestionFind the derivative of the function $y = 2^x - \sqrt[3]{x^2} + 4 \arccos x$.

Studdy Solution
Combine the derivatives from the previous steps to find the derivative of the entire function $y$.
The derivative of $y$ is:
$$y' = \frac{d}{dx} (2^x) + \frac{d}{dx} (-\sqrt[3]{x^2}) + \frac{d}{dx} (4 \arccos x)$$
$$y' = 2^x \ln(2) - \frac{2}{3x^{1/3}} - \frac{4}{\sqrt{1-x^2}}$$
The derivative of the function is:
$$y' = 2^x \ln(2) - \frac{2}{3x^{1/3}} - \frac{4}{\sqrt{1-x^2}}$$