Math  /  Measurement

Question Differentiate the function f(θ)=secθ5+secθf(\theta) = \frac{\sec \theta}{5 + \sec \theta}.

Studdy Solution
This is the simplified form of the derivative.
f(θ)=5secθtanθ(5+secθ)2 f'(\theta) = \frac{5\sec \theta \tan \theta}{(5 + \sec \theta)^2}
The derivative of the function f(θ)=secθ5+secθ f(\theta) = \frac{\sec \theta}{5 + \sec \theta} with respect to θ \theta is 5secθtanθ(5+secθ)2 \frac{5\sec \theta \tan \theta}{(5 + \sec \theta)^2} .

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