Question Find the derivative of $y = \sqrt{8 + t^2}$.

Studdy Solution
Write the final expression for the differential of $y$ with respect to $t$.
$$\mathrm{d}y = \frac{t}{\sqrt{8 + t^2}} \mathrm{d}t$$
The differential of $y = \sqrt{8 + t^2}$ with respect to $t$ is $\mathrm{d}y = \frac{t}{\sqrt{8 + t^2}} \mathrm{d}t$.