Math  /  Calculus

QuestionFind the tangent line equation for the function f(x)=exln(x)f(x)=e^{-x} \ln (x) at the point (1,0)(1,0).

Studdy Solution
implify the equation to get the final answer.
y=e(x)y = e^{-}(x -)The equation of the tangent line to the graph of the function at the given point is y=e(x)y = e^{-}(x -).

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