Math  /  Calculus

QuestionFind the tangent line equation for f(x)=xf(x) = \sqrt{x} at the point (1,1).

Studdy Solution
implify the equation of the tangent line.
y=12x+12y = \frac{1}{2}x + \frac{1}{2}So, the equation of the tangent line to the graph of f(x)=xf(x) = \sqrt{x} at the point (1,1)(1,1) is y=12x+12y = \frac{1}{2}x + \frac{1}{2}.

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