QuestionFind the equations of the tangent line and normal lines to the graph of the function $f(x)=-6 \sin x$ at $x=\pi / 2$. a) Tangent line: ? $\square$ b) Normal line: $\square$ $\square$

Studdy Solution
Use the point-slope form to write the equation of the normal line:
Since the normal line is vertical, it has the form $x = x_1$.
For the normal line: $$x = \frac{\pi}{2}$$
The equations are: a) Tangent line: $y = -6$ b) Normal line: $x = \frac{\pi}{2}$